Featured image of post 206. 反转链表

206. 反转链表

题目描述

给你单链表的头节点 head ,请你反转链表,并返回反转后的链表。

示例 1:

  • 输入:head = [1,2,3,4,5]
  • 输出:[5,4,3,2,1]

示例 2:

  • 输入:head = [1,2]
  • 输出:[2,1]

示例 3:

  • 输入:head = []
  • 输出:[]

解法一:双指针

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/**
 * Definition for singly-linked list.
 * type ListNode struct {
 *     Val int
 *     Next *ListNode
 * }
 */
func reverseList(head *ListNode) *ListNode {
    if head == nil || head.Next == nil {
        return head
    }

    var prev *ListNode
    cur := head
    for cur != nil {
        next := cur.Next
        cur.Next = prev
        prev = cur
        cur = next
    }
    return prev
}

解法二:递归

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/**
 * Definition for singly-linked list.
 * type ListNode struct {
 *     Val int
 *     Next *ListNode
 * }
 */
func reverseList(head *ListNode) *ListNode {
    if head == nil || head.Next == nil {
        return head
    }
    newHead := reverseList(head.Next)
    head.Next.Next = head
    head.Next = nil
    return newHead
}
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